It makes a non-type template parameter of type T with a default value of 0.
C++17 introduced this alternative syntax:
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template <auto T = 0>
T moduloOf(T a, T b) {
return a % b;
}
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@mbozzi T is a type in the original code. In your code T isn't a type, but it's being used as a type, so the code doesn't compile.
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template<typename T, T = 0>
T moduloOf(T a, T b) {
return a % b;
}
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The template takes one typename argument and one non-type argument.
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auto answer1 = moduloOf<int>( 7, 3 ); // non-type has value 0
auto answer2 = moduloOf<int,42>( 7, 3 ); // non-type has value 42
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The non-type template parameter is unnamed and is not used anywhere in the templated function.
Does the "initialized with value 0" limit what type the T can be?
Similar to concepts in modern C++?
Last edited on
Indeed:
"initialized with value 0" limit what type the T can be?