Problems with a program, switch statement

[grooviqw]

Hi i made a program with switch, if i input a character to show me if is vowel or a consonant if is letter and to show me if is odd or even if it's number
i don't understand where is the mistake..i need obligatory to use switch

#include <iostream>

using namespace std;

int main()
{
  char n;
  cout<< "Input the character : "; cin>>n;
  switch(n){
  case 'A':
  case 'a':
  case 'E':
  case 'e':
  case 'I':
  case 'i':
  case 'O':
  case 'o':
  case 'U':
  case 'u':
  cout<<n<< " vowel ."<<endl; break;
  case 'B':case 'b':case 'C':case 'c':case 'D':case 'd':
  case 'F':case 'f':case 'G':case 'g':case 'H':case 'h':
  case 'J':case 'j':case 'K':case 'k':case 'L':case 'l':
  case 'M':case 'm':case 'N':case 'n':case 'P':case 'p':
  case 'Q':case 'q':case 'R':case 'r':case 'S':case 's':
  case 'T':case 't':case 'V':case 'v':case 'W':case 'w':
  case 'X':case 'x':case 'Y':case 'y':case 'Z':case 'z':
  cout<<n<< " is consonant ."<<endl; break;
  }
  switch(n%2==0){
  case 0: cout<<n<< " is even"; break;
  case 1: cout<<n<< " is odd"; break;
  default:cout<<n<< " is simbol"<<endl; break;
  
  }
  return 0;
}

[salem c]

https://www.cplusplus.com/articles/jEywvCM9/
Carry on with your cases

case '0':case'2'....
cout<<n<< " is even"; break;

[lastchance]

@denispopescuo,
Are you reporting people who are actually assisting you in answering your questions?

As @salem c links:
- use code tags, so that we can run your code online.

As @salem c wrote:
- to get the different types of number then continue with the cases.

Stop hitting the Report button (as you've done in other posts) and start reading what people have written.

[grooviqw]

sorry, i'm new here

[grooviqw]

now i used code tags

[deleted account xyzzy]

Using required switch statements, with a few checks if the input is a letter or a numeric digit:

#include <iostream>
#include <cctype>   // ::isalpha, ::tolower, ::isdigit
// http://www.cplusplus.com/reference/cctype/

int main()
{
   std::cout << "Input a single character: ";
   char n;
   std::cin >> n;
   std::cout << '\n';

   // let's check if the input is a letter or a numeric digit

   if (::isalpha(n))  // is it a letter?
   {
      switch (::tolower(n))  // temp convert to lower case
      {
      case 'a': case 'e': case 'i': case 'o':  case 'u': // is it a vowel?
         std::cout << n << " is a vowel.\n"; break;

      default:  // if not, consonant
         std::cout << n << " is a consonant.\n"; break;
      }
   }
   else if (::isdigit(n))  // is it a numeric digit?
   {
      switch ((int)(n - '0') % 2)  // temp convert to integer
      {
      case 0: std::cout << n << " is a number and is even.\n"; break;

      case 1: std::cout << n << " is a number and is odd.\n"; break;
      }
   }
   else // not a letter or numeric digit
   {
      std::cout << n << " is symbol\n";
   }
}

When the input is a character converting to lower (or upper) case reduces the number of case statements required.

Also, when working with a letter if it isn't a vowel by default it is a consonant.

The is-a-number switch is not really needed since all you are looking for is whether a number is odd or even. It could be rewritten:

      if ((int) (n - '0') % 2)  // temp convert to integer
      {
         std::cout << n << " is a number and is odd.\n";
      }
      else
      {
         std::cout << n << " is a number and is even.\n";
      }

[grooviqw]

thank you