Python help list and dictionaries

geosnipes (18)
I wish to use a list to access each dictionary. How do I do this? The problem is at the function get_class_average. I want it to go through eash item in the list which is the same as a dictionary name and find its average. however it is treating each item in the list as a string and not a dictionary which i understand why . But i do not know how to let it treat it as a dictionary. How do I?

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
 
lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}
students=['lloyd','alice','tyler']
    
# Add your function below!
def average (numbers):
    total=sum(numbers)
    total=float(total)
    return total/len(numbers)
    
def get_average(student):
    homework=average(student['homework'])
    quizzes=average(student['quizzes'])
    tests=average(student['tests'])
    return .1*homework+.3*quizzes+.6*tests
    
def get_letter_grade(score):
    if score>=90:
        return "A"
    elif score>=80:
        return "B"
    elif score>=70:
        return "C"
    elif score>=60:
        return "D"
    else:
        return "F"

def get_class_average(students):
    results=[]
    for student in students:
        avg=get_average(student)
        results.append(avg)
        print avg
    return average(results)

print get_letter_grade(get_average(lloyd))
print get_class_average(students)
Topic archived. No new replies allowed.