std-C++ in QT4

Helegurbann (156)
Hi,How can i do this?
Example:
This is real code in qt:
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#include <qt/QPushButton.h>
#include <qt/QApplication.h>
#include <qt/QFont.h>



int main(int argc, char *argv[])
{
    QApplication app(argc,argv);
    QPushButton cikis("Quit");
    cikis.resize(150,50);
    cikis.setFont(QFont("Times",16,QFont::Bold));
    QObject::connect(&cikis,SIGNAL(clicked()),&app,SLOT(quit()));
    cikis.show();
    return app.exec();
}


But i want to this method:
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#include <qt/QPushButton.h>
#include <qt/QApplication.h>
#include <qt/QFont.h>
#include <stdio.h>
using namespace std;

int main(int argc, char *argv[])
{
    QApplication app(argc,argv);
    QPushButton cikis("Quit");
    cikis.resize(150,50);
    cikis.setFont(QFont("Times",16,QFont::Bold));
    QObject::connect(&cikis,SIGNAL(clicked()),&app,SLOT(exit(1)));
    cikis.show();
    return app.exec();
}


Why is not run this?Is this cause run with moc?
Last edited on
srinathduraisamy (17)

You can only use methods declared as Slots for QObject::connect SLOT.
quit method is declared as a slot method in QApplication class and exit is not a slot.

If you want, you can inherit a class from QApplication and declare your own slot method and call exit( 1 ) in your slot method.

Hope it helps.








Helegurbann (156)
I tried ur said method in QApplication,QPushButton,QCoreApplication..But i am researching.Thank u for help.
achab (1)
Try this:
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#include <QObject>
#include <QPushButton>
#include <QApplication>
#include <QFont>
#include <stdio.h>
using namespace std;


class Exit:public QObject
{
    Q_OBJECT
public:
    Exit(int exitNumber, QObject *parent =0):QObject(parent),m_exitNumber(exitNumber){}
    virtual ~Exit(){}

public slots:
    void exit(){qApp->exit(m_exitNumber);}
private:
    int m_exitNumber;

};


int main(int argc, char *argv[])
{
    QApplication app(argc,argv);
    QPushButton cikis("Quit");
    Exit* failExit = new Exit(1);
    cikis.resize(150,50);
    cikis.setFont(QFont("Times",16,QFont::Bold));
    QObject::connect(&cikis,SIGNAL(clicked()),failExit,SLOT(exit()));
    cikis.show();
    return app.exec();
}

#include "main.moc"

Helegurbann (156)
I tried this.And taken this error:
 
 
36 F:\QT\QT_My_Func.cpp main.moc: No such file or directory.


How can i do this dont use qmake?
Last edited on
Helegurbann (156)
I tried this:
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#include <qt/QObject.h>
#include <qt/QPushButton.h>
#include <qt/QApplication.h>
#include <qt/QFont.h>
#include <stdio.h>
using namespace std;


class Exit:public QObject
{
    Q_OBJECT
public:
    Exit(int exitNumber, QObject *parent =0):QObject(parent),m_exitNumber(exitNumber){}
    ~Exit();

public slots:
    void exit(){qApp->exit(m_exitNumber);}
private:
    int m_exitNumber;

};


int main(int argc, char *argv[])
{
    QApplication app(argc,argv);
    QPushButton cikis("Quit");
    Exit* failExit = new Exit(1);
    cikis.resize(150,50);
    cikis.setFont(QFont("Times",16,QFont::Bold));
    QObject::connect(&cikis,SIGNAL(clicked()),failExit,SLOT(exit()));
    cikis.show();
    return app.exec();
}


And i taken this:
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  [Linker error] undefined reference to `vtable for Exit' 
  ld returned 1 exit status 
 F:\QT\Makefile.win [Build Error]  [QT_My_Func.exe] Error 1
cdel (13)
IIRC, you can't specify using namespace std; in Qt applications. There are constructs in the std library which is incompatible with the Mock Compiler (moc).

Try instead of omitting using namespace std and just using the scope resolution operator (::) for explicitly calling std function.

For example, instead of doing:

cout << "Hello World" << endl;

You would use:

std::cout << "Hello World" << std::endl;
Helegurbann (156)
This method did not to avail.
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