Memory allocation

Summerson Goncalves (14)
Hello!!!

why the result is different...how the memory allocation was made ?
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#include<iostream>
using namespace std;
struct teste{
              int numero;
              struct teste *ptr;
            };
int main(void)
{
   teste *p=new teste;
   cout<<"Endereco de p->ptr  "<<p->ptr;
   cin.get();
}


p->ptr =0 , if i put one more pointer: *ptr2, the result is different.
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#include<iostream>
using namespace std;
struct teste{
              int numero;
              struct teste *ptr;
              struct teste *ptr2;  // here
       };
int main(void)
{
   teste *p=new teste;
   cout<<"Endereco de p->ptr  "<<p->ptr;
   cout<<"\nEndereco de p->ptr2 "<<p->ptr2; // here
   cin.get();
}

the pointer receive an address...?
(sorry my bad english...)
Cubbi (4774)
The pointers aren't initialized, they hold whatever values were in memory.
Use teste *p = new teste(); if you want them to be zeroed out. Or write a constructor.
Last edited on
Summerson Goncalves (14)
but...the first result is zero "0".
the second result are two addresses....
the first pointer in the first code was zero...
the second should be the same result...or not ?

I just wanna learn how it works....can you explain ?

thanks...
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