operator= from class to some other type

[TheDestroyer]

I have a simple question, to which I couldn't find a direct answer.

If I have a class:

template <typename T>
class myClass
{
    T x;
};

How does the prototype of operator= look like if I want to make the following code compilable:

double t;
myClass<double> cls;

t = cls;

so that after the last line, I'll have t = cls.x automatically. Is that possible?

Thank you for any efforts.

[AleaIactaEst]

As far as i know it's impossible because operator= has to be a member of a class.

Instead you could make use of the cast operator:

#include <iostream>
using namespace std;

class test {
	public:
		double A;
		
		operator double() { return A; }
};


int main(int argc, char **argv) {
	test tt;
	tt.A = 4.;
	
	double k = tt;

	cout << k;
	
	return 0;
}

This prints 4 to standart output.

[TheDestroyer]

Thanks a lot, man! That's exactly what I was looking for :)

Cheers!