Confused at Variable Scops

mahdi87gh (3)
Hi
consider this Program
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#include <iostream.h>
int x; //global variable


void main()
{
 int x; //local variable
 
 for(int x=0; x<10; x++)
 {
   cout<<"x in for="<<x;
   //how to access global x ?
   //how to access local x ?
 }
}

I know i can access to the global x with :: , but how should i access to the local x variable in the for?
Telion (129)
I'm pretty sure there is no way to access the outer local x from inside the for loop.

Consider a case like this:

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int main()
{
    int x;
    {
        int x;
        {
            int x;
            {
                int x;
                //how would you possibly choose which x to use from here?
            }
        }
    }

    return 0;
}


Because shadowing can get this complicated, there is no mechanism for choosing a local variable other than the one with the smallest scope.
Last edited on
eypros (329)
Also I noticed you are using void main() and <iostream.h> and I am guessing your compiler is quite old.
Consider getting a newer one (there are a lot of them free of charge).
mahdi87gh (3)
thanks
Aramil of Elixia (772)
when you do there is no .h iostream and main has to be type int
closed account (10oTURfi)
Level of uselessness: 100

If you are really into having dozens of integers of same name, put each in different namespace.
mahdi87gh (3)
our teacher asked this question.
thanks anyway, i got it
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