Linked Binary Tree with a vector

Hello guys, I found a closed topic about the Lined Binary Tree and its interesting for me how can I implement a vector in it, so the user will be able to choose the numbers in the tree.I almost understand the algorithm but its difficult for me to find the way, because of those children (the left child and right child).Can someone help me with it?Here is the code :

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#include <iostream>
using namespace std;

// Code Fragment: LinkedBinaryTree1

template <typename Object>
class LinkedBinaryTree {
protected:
  // ... (insert Node definition here)
  //Code Fragment: Node
  struct Node {						// a node in the tree
    Object      element;				// the element
    Node*       parent;					// parent
    Node*       left;					// left child
    Node*       right;					// right child
    Node() : element(Object())				// default constructor
      { parent = left = right = NULL; }
    Node* sibling() const {				// get our sibling
      return (this == parent->left ? parent->right : parent->left);
    }
  };
  typedef Node* NodePtr;				// a node pointer
public:
  // ... (insert Position definition here)
  //Code Fragment: Position
  class Position {				// position in the tree
  private:
    NodePtr node;				// pointer to the node
  public:
    Position(NodePtr n = NULL)	// constructor
      { node = n; }
    Object& element() const		// get element
      { return node->element; }
    bool isNull() const 		// null position?
      { return node == NULL; }
    friend class LinkedBinaryTree;	// allow access
  };

private: 						// member data
  NodePtr    theRoot;			// pointer to the root
  int        sz;				// number of nodes
protected: 						// protected utilities
  // ... (insert LinkedBinaryTree utilities here)
//Code Fragment: LinkedBinaryTree2
  // ... (utilities for LinkedBinaryTree)
  NodePtr nodePtr(const Position& v) const 	// convert to NodePtr
    { return v.node; }
  bool isExternal(NodePtr n) const 			// is node external?
    { return (n->left == NULL && n->right == NULL); }
  bool isInternal(NodePtr n) const 			// is node internal?
    { return ! isExternal(n); }
  bool isRoot(NodePtr n) const 				// is node the root?
    { return (n == theRoot); }
  void setRoot(NodePtr r)				    // make r the root
    { theRoot = r;  r->parent = NULL; }
  void replaceElement(NodePtr n, const Object& o)	// replace element
    { n->element = o; }
  void swapElements(NodePtr n, NodePtr w) {		// swap elements
    Object temp = w->element;
    w->element = n->element;
    n->element = temp;	
  }
  void expandExternal(NodePtr n) {			// expand external node
    n->left   = new Node;	n->left->parent = n;
    n->right  = new Node;	n->right->parent = n;
    sz += 2;
  }
  NodePtr removeAboveExternal(NodePtr n) {	// remove n and parent
    NodePtr p = n->parent;
    NodePtr s = n->sibling();
    if (isRoot(p)) setRoot(s);				// p was root; now s is
    else {
      NodePtr g = p->parent;				// the grandparent
      if (p == g->left)	    g->left  = s;	// replace parent by sibling
      else 		    g->right = s;
      s->parent = g;
    }
    delete n; delete p;					// delete removed nodes
    sz -= 2;						    // two fewer nodes
    return s;
  }  
public:
  LinkedBinaryTree()					// constructor
    { theRoot = new Node; sz = 1; }
  int size() const  					// size of tree
    { return sz; }
  bool isEmpty() const 					// is tree empty?
    { return (sz == 0); }
  Position root() const 				// returns root
    { return Position(theRoot); }
  Position leftChild(const Position& v) const 		// returns left child
    { return Position(nodePtr(v)->left); }
  Position rightChild(const Position& v) const 		// returns right child
    { return Position(nodePtr(v)->right); }
  // ... parent(), and sibling() are omitted but similar)
  bool isRoot(const Position& v) const 			// is v the root?
    { return isRoot(nodePtr(v)); }
  bool isInternal(const Position& v) const 		// is v internal?
    { return isInternal(nodePtr(v)); }
  bool isExternal(const Position& v) const 		// is v external?
    { return isExternal(nodePtr(v)); }
  void replaceElement(const Position& v, const Object& o)
    { replaceElement(nodePtr(v), o); }			// replace element
  void swapElements(const Position& v, const Position& w)
    { swapElements(nodePtr(v), nodePtr(w)); }	// swap elements
  void expandExternal(const Position& v)
    { expandExternal(nodePtr(v)); }			    // expand external node
  Position removeAboveExternal(const Position& v)	// remove v and parent
    { return Position(removeAboveExternal(nodePtr(v))); }
  // ... (housekeeping and iterator functions omitted)
};

class Int {
   public:      
       Int() { counter++; num = counter; }       
   private:
        static int counter;
        int num;
    friend ostream& operator<<(ostream& out, Int i);                               
};

ostream& operator<<(ostream& out, Int i)
{ out << i.num << " ";
  return  out;
}      

typedef LinkedBinaryTree<Int> Tree;
typedef Tree::Position Position;

void binaryInorderPrint(const Tree& T, const Position& v) 
{ if (T.isInternal(v))        // visit left child
     binaryInorderPrint(T, T.leftChild(v));
  cout << v.element();      // print element
  if (T.isInternal(v))        // visit right child
     binaryInorderPrint(T, T.rightChild(v));
}

int Int::counter = 0;

int main()
{ LinkedBinaryTree<Int> btree;
  btree.expandExternal(btree.root());
  binaryInorderPrint(btree, btree.root());  
  cout << endl;
  btree.expandExternal(btree.leftChild(btree.root()));  
  binaryInorderPrint(btree, btree.root());  
  return 0;
}  
I am still looking at it, and I am getting more and more convinced that a vector shouldnt be used.Is there any other way?
Hi again, you mean you want your binary tree to hold vectors instead of integers?
Hi again Dacster.Its interesting for me how this code can be modified, so the user will be able to choose the numbers.So I think a vector should be used to store the integers, or am I wrong?
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