making codes shorter

[ayish100]

int n1, n2, n3, n4, n5;
int a, b, c, d, e;
    cout << "Enter 5 numbers:\n";
	cin>>n1>>n2>>n3>>n4>>n5;
		if(n1==n2 && n1==n3 && n1==n4 && n1==n5)
			cout<<"The numbers you have entered are equal! \n\n";
		else
		{
        if (n1 > n2)
				a = n1;
		else
				a = n2;
		if (n3 > n4)
				b = n3;
		else
				b = n4;
		if (n5 > a)
				c = n5;
		else 
				c = a;
		if (b > c)
				d = b;
		else 
				d = c;
		cout<<d<< " is  the highest number!\n\n";
		 }

is there anyway to shorten this code?? please help.. and how can i input multiple values with just one command line??

[PanGalactic]

In the future, questions such as this are best asked (and answered) in the beginners forum.

The simplest way to shorten the code is to use vectors/arrays and loops.

[Breadman]

	int numbers[5];

	for(int i = 0; i < 5; i++)
	{
		cin >> numbers[i];
	}

	int highest = 0;

	for(int i = 0; i < 5; i++)
	{
		if(numbers[i] > highest)
		{
			highest = numbers[i];
		}
	}

	cout << highest << "is the highest";

smth like this. not sure if its shorter :P

[ayish100]

it is.. i guess.. lol.. xD

tnx for the help..

but by any chance.. is there anyway to remake the original code with another formula but with the same output using (nested) if else??and how?

@pan.. sorry.. this will be the last..

[PanGalactic]

@Breadman: please don't answer homework questions with working code.

[Breadman]

He had it correct i just made it shorter

[buffbill]

There is no need for two loops:

int highest=0;
int numbers[5];

	for(int i = 0; i < 5; i++)
	{
		cin >> numbers[i];
               if(numbers[i]>highest)highest=numbers[i];
	}
cout<<"highest = "<<highest<<endl;

[Athar]

Or just:

const int numberCount=5;
int numbers[numberCount];
for (int i=0;i<numberCount;i++)cin >> numbers[i];
cout<< "highest = " << *max_element(numbers,numbers+numberCount) << endl;