Printing the name of a function

[krishnendu]

Is it possible to print the name of the function from where the print method is being called? Go through the following pseudo code.

void foo (void)
{
	cout << XXX << endl;
	// XXX is some kind of macro, like __LINE__,
	// that contains the name of the current function.
	// i.e. void foo (void)
}

Similarly, in the context of C++, it is possible to print the name a class with typeid (*this).name (). But what about the name of a method?

[Abramus]

I think that most compilers support __FUNC__, but it is not in the standard.

[krishnendu]

I got the answer. In general, it is __FUNCTION__. This works well both with gcc and vc2005. __func__ is not supported in vc2005.
In gcc, there is __PRETTY_FUNCTION__ which prints the entire name of the function, e.g. int Class::foo (int arg).

Thanks