error in 'if' checking

[acpaluri]

#include <stdio.h>

int main (void) {
	int x = 0;
	float y  = 0.0;
	
	scanf("%d%f",&x, &y);
	
	if (!( (x > 0) && (x<=2000) && (y>=0) && (y<=2000) ) )
		;
	else{
	
		if (x%5!=0 || x+.50>y)
			printf("%.2f\n", y);
		else 
			printf("%.2f\n", y-x-.50);
	}
	
	return 0;
}

For the following input: 14.50 15.00 the answer is supposed to come as 15. However it is coming as 0.50 which is apparently wrong coz as x is an integer program reads 14.5 as 14 and the condition 'x%5!=0' happens to be true. Hence it should execute the first print but it is executing the second print. Can anyone tell me why?

[z05DSL3A]

if you put in 14.5 and 15.0 into the program x will be 14 and y will be 0.5 and y is being printed.

It takes the first int out of the input stream, leaving

.5 15.0

, it then take the first float that is .5.

[acpaluri]

Thanks!! Didnt know integer truncation was done this way.