problem with void pointer

[sangfroid]

Hi,

I just wrote a simple program, but it is not working as expected..

#include <stdio.h>
main()
{
void *p;
char chr[]= {"Harry Potter"};
p=(char*)chr;
printf("%c",(char *)p);
}

Why it is not printing "H" here ? Is it not supposed to print letter H ??

[helios]

You have to dereference the pointer.

[sangfroid]

Can you provide some hint on it ??

I have tried with

p=(char*)&chr;
printf("%c",(char *)p);
}

too

It doesn't work either

[Kyon]

#include <stdio.h>
int main() // Don't forget the int part, not all compilers will automatically add it
{
   void *vp;
   char chr[] = {"Harry Potter"};
   vp = (char*)chr;
   printf("%c",*vp);
}

[Disch]

Except you can't dereference a void pointer.

void *p;
char chr[]= {"Harry Potter"};
p=chr;
printf("%c",*(char *)p);
}

Note on line 4 you have to cast to a non-void pointer (in this case a char pointer), then you dereference the pointer with *.

Of course you could just get rid of the useless void pointer and use chr directly:

char chr[]= {"Harry Potter"};
printf("%c",*chr);   // or chr[0] 

void pointers are evil.

[Kyon]

Haven't worked with them for a while, forgot how to use them, Disch is indeed right. Although, void pointers can be useful when working with threads; to interchange data between the two threads you need a void pointer.