Need help on my assignment

[bryan123]

Create the logic for the dice game Twig, in which a player can compete with the computer. The
object of the game is to be the first to score 10 points. The user and computer take turns “rolling” a
pair of dice following these rules:
 On a turn, each player rolls two dice. If no 1 appears, the dice values are added to a running total
for the turn, and the player can choose whether to roll again or pass the turn to the other player.
When a player passes, the accumulated turn total is added to the player’s game total.
 If a 1 appears on one of the dice, the player’s turn total becomes 0; in other words, nothing more
is added to the player’s game total for that turn, and it becomes the other player’s turn.
 If a 1 appears on both of the dice, not only is the player’s turn over, but the player’s entire
accumulated total is reset to 0.
 When the computer does not roll a 1 and can choose whether to roll again, generate a random
value from 1 to 2. The computer will then decide to continue when the value is 1 and decide to
quit and pass the turn to the player when the value is not 1.


My Lecturer told me to use If while but idk how

[kbw]

We can help, but can't do it for you.

If you need help here, you should try. If you're stuck, explain what you're stuck with and post your code.

Good luck.

[bryan123]

#include <iostream>
#include<stdlib.h>
#include<time.h>

using namespace std;
int main()
{

int repeat = 0;
int score1=0;
int score2=0;
int sum =0;
int sum1;
int sum2;
int round1=0;
int round2=2;
int round3=0;
int number1 = 1 || 2 || 3 || 4 || 5 || 6;
int number2 = 1 || 2 || 3 || 4 || 5 || 6;
int number3 = 1 || 2 || 3 || 4 || 5 || 6;
int number4 = 1 || 2 || 3 || 4 || 5 || 6;
int value1 = number1 + number2;
int value2 = number3 + number4;
{
srand(time(0));

for (int round = 1; round<4;round++){

cout << "Press enter to roll your 1st dice:" << endl;
cout << "Your 1st: " << rand() % 6 + 1 << endl;
cin >> number1;

cout << "Press enter to roll your 2nd dice:" << endl;
cout << "Your 2nd: " << rand() % 6 + 1 << endl;
cin >> number2;
cout << "Your Total: " << number1 + number2 << endl;
sum1 = number1 + number2;

cout << "Press enter to roll computer's 1st dice:" << endl;
cout << "Computer's 1st: " << rand() % 6 + 1 << endl;
cin >> number3;

cout << "Press enter to roll computer's 2nd dice:" << endl;
cout << "Computer's 2nd: " << rand() % 6 + 1 << endl;
cin >> number4;
cout << "Computer's Total: " << number3 + number4 << endl;
sum2 = number3 + number4;

cout << "Your score: " << sum1 << " Computer's score: " << sum2 << endl;
cin.get() >>round1;

if (sum1>=10)
{
cout << "Game over You win!" << endl;
round =4;

if (sum2>=10)

cout << "Game over Opponent win!" << endl;
round =4;
}

}
}
}


is it possible to loop a random result and accummulate at the same time??

[seeplus]

Without the game logic and just obtaining the thrown dice values, consider as an alternative program structure:

#include <iostream>
#include <string>
#include <cstdlib>
#include <ctime>

int main()
{
	constexpr unsigned Require {10};
	constexpr unsigned noDice {2};
	constexpr const char* const nums[] {"1st", "2nd"};
	constexpr const char* const names1[] {"your", "computer's"};
	constexpr const char* const names2[] {"You", "Computer"};
	enum Players {YOU, COMP, NOPLAY};
	std::string l;	// Dummy
	unsigned totals[NOPLAY] {};

	srand(static_cast<unsigned>(time(nullptr)));

	for (unsigned r = 1; totals[YOU] < Require && totals[COMP] < Require; ++r) {
		unsigned rolled[NOPLAY][noDice] {};

		std::cout << "\nRound " << r << '\n';

		for (unsigned t = 0; t < NOPLAY; ++t) {
			for (unsigned d = 0; d < noDice; ++d) {
				std::cout << "Press enter to roll " << names1[t] << " " << nums[d] << " dice: ";
				std::getline(std::cin, l);
				rolled[t][d] = rand() % 6 + 1;
				totals[t] += rolled[t][d];
				std::cout << names2[t] << " rolled a " << rolled[t][d] << '\n';
			}

			std::cout << names1[t] << " total: " << totals[t] << '\n';
		}

		std::cout << "Your score: " << totals[YOU] << " Computer's score: " << totals[COMP] << '\n';
	}

	if (totals[YOU] >= Require)
		std::cout << "Game over. You win!\n";
	else
		std::cout << "Game over. Computer wins!\n";
}

[kbw]

is it possible to loop a random result and accummulate at the same time?

We can loop a random number of times as follows:

    srand(time(0));

    int max_rounds = rand() % 4; // choose a random number of rounds, max 4
    cout << "Playing with " << max_rounds << " rounds" << endl;

    for (int round = 1; round < max_rounds;round++)
    {

You are accumulating sum1 and sum2 in your code, so I'm not sure what the accumulate question is about.