Assign reference address to variable

[dbjohn]

At the beginning of the tutorial at http://www.cplusplus.com/doc/tutorial/pointers/ the first section on reference uses and example of assigning the address to a variable. For example

 
andy = 25;
fred = andy;
ted = &andy; 

So that ted will contain some address value like 345342. I wanted to try and replicate that but there isn't any code to try and implement it; Was this more like pseudocode? Here is an attempt I made to try and print out that address value. Commented out you can see variations that didn't work.

int main ()
{
	char a = 'x';
	//int myref;		//produces error
	//int& myref = 0;		//not work
	//char myref;		//not work

	unsigned int& myref = &a;

	//myref = &a;		//not work

	cout << "a is " << a << endl;
	cout << "myref is " << myref << endl;
	return 0;
}

This is an example that I found which produces similar output

int main()
 {
   float fl=3.14;
   std::cout << "fl's address=" << (unsigned int) &fl << std::endl;
   return 0;
 }

But I was hoping there was a way to produce what is given in the examples in the tutorials? Do you have to resort to using pointers?

[Disch]

But I was hoping there was a way to produce what is given in the examples in the tutorials? Do you have to resort to using pointers?

Why is that "resorting"? That's exactly what pointers are.

[Fworg64]

Could you cast it as a int or somthing?

cout << hex << ((int) mypointer);

[Disch]

I suppose you could, but it would be pointless and would destory the type system.

Why not just do this:

cout << mypointer;