does the or( || ) operator use short circuit evaluation?

[unregistered]

just like the and( && ) operator?

[Athar]

Yes, the right operand will not be evaluated if the first was already true.

[moorecm]

That is, assuming that the operator has not been overloaded. If it has, it's semantics will change because the order of evaluation of function arguments is not defined.

[rahulroot]

&& and || operator uses short circut evaluation and in C++ we should avoid them to overload.

operator && (func1,func2) will be called as (fun1 && fun2),in this case we don't know which func will execute first and that is not in sync with C,which says fun2 will be evaluated only if func1 is true.