create a human readable output file with char arrays

[Norej]

The program must be able to work for an input file that contains following information:

# of temperature readings
timestamp
temperature
[# of temperature readings] [time stamp] [temperature]

input file example:
2
200707211245 F70.5
200708220812 C19.97

without using string objects how can I use char arrays to rearrange the data so when printed to the output it is in a human-readable string. (see below)

I also need to be able to convert Farenheit to Celcius, and then calculate the average temperature, and display it to the output.

output file example:

BIODATA Formatted Output
<blank space>
21.38 C --- recorded on 07/21/2007 at 1245
19.97 C --- recorded on 08/22/2007 at 0812
<blank space>
Average Temp --- 20.68 C


what I have so far is not much but here it is. There are some unused variables but that's because I was just messing around trying to figure it out.

#include <iostream>
#include <fstream>

using namespace std;

void OutputFormat(ofstream &fout);

int main()
{

int num_of_temp_readings = 0;

char time_stamp[256];

double temperature = 0,
avg_temp = 0;




ofstream fout;
fout.open("Filtered_biodata.dat");

if(!fout)
{
cout << endl << endl
<< "Program terminated!" << endl << endl
<< "Output failed to open." << endl;

}

ifstream fin;
fin.open("biodata.dat.txt");

if(!fin)
{
cout << endl << endl
<< "Program terminated!" << endl << endl
<< "input failed to open." << endl;
}





fin >> num_of_temp_readings;


for(int i = 0;i < num_of_temp_readings; i++)
{
fin.getline( time_stamp, 256);
cout << time_stamp << endl;

}



fout.close();
fin.close();

return 0;
}

[Norej]

I posted something similar a few days ago but I thought I should post again since my original post was very vague.

[dutch]

Why didn't you bother responding to the people that tried to help you there?
And use code tags when posting code.

[Norej]

Sorry about that I am new to site and don’t actually know how to use code tags. I saw it on another post so I will edit them in

[againtry]

It's now up to you to convert what's in the buffer each time to formatted output.

#include <iostream>
#include <fstream>

int main()
{
    int no_records = 0;
    
    char buffer[200];

    std::ifstream myfile ("bio_data_in.txt");
    if (myfile.is_open())
    {
        myfile >> no_records;
        
        for(int i = 0; i < no_records * 2; i++)
        {
            myfile >> buffer;
            std::cout << "Line: " << i/2 << " - " << buffer << '\n';
        }
        myfile.close();
    }
    else
        std::cout << "Unable to open file";
    
    return 0;
}