doubt about new operator
1)int a = 100; -> allocates memory at compile time in stack
2) int *q = new int(100); -> allocates memory at run time in heap
With stmt1, we can directly use 'a' in the computations where as with stmt2, we have to use q indirectly to get the value 100 in computations.
What will be the difference if I use stmt2 in place of stmt1?
2) int *q = new int(100); -> allocates memory at run time in heap
With stmt1, we can directly use 'a' in the computations where as with stmt2, we have to use q indirectly to get the value 100 in computations.
What will be the difference if I use stmt2 in place of stmt1?
Statement 1 allocates space on the stack for a and assigns it value 100.
Statement 2 allocates space on the stack for q and assings it the value of the request for memory on the heap for an int that has been initialised with value 100.
q holds the value of the address (in the heap) where the int is reserved, or null if the allocation failed.
If you use q without dereferencing it, you'll the address. The compiler's type system should place some restrictions on the use of q and *q to help you identify incorrect usage.
Statement 2 allocates space on the stack for q and assings it the value of the request for memory on the heap for an int that has been initialised with value 100.
q holds the value of the address (in the heap) where the int is reserved, or null if the allocation failed.
If you use q without dereferencing it, you'll the address. The compiler's type system should place some restrictions on the use of q and *q to help you identify incorrect usage.
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