Comparing 2 literal strings

whitenite1 (1785)
I saw a member asking about a game like 'Boggle', and thought that sounded like a nice project to write. I made a struct to hold the words in a dictionary..
(370,100 words in total)

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struct Dictionary_Words
{
	string word;
};


I have the game where it checks the Boggle grid and can find the word, or group of letters, you input. That works fine. But, I can't find a way to compare the word entered with a word in the dictionary.

Search_Word is a string
word_list[z].word is a string

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if(In_Grid)
{
	// My info to show the word was found in grid 
        cout << "Found the word " << Search_Word << ".." << endl;
	In_Dictionary = false; // bool
	int size = word_list.size(); // struct dictionary
	for(z=0; z < size;z++)
	{
		gotoXY(5,38);
		cout << "Checking word #" << word_list[z].word << "       ";
// Below says a match of 'a' is found NO MATTER what word I entered		
             if(Search_Word.compare(word_list[z].word))
		{
		gotoXY(5,39);
		cout << "Found word in the dictionary";
		z = size+1;
		In_Dictionary = true;
	}
}
else
	cout << "That was NOT a word found in the dictionary.." << endl;


How can I compare the two strings without having to resort to convert them to chars??
JLBorges (13770)
Case insensitive comparison:
if( Search_Word == word_list[z].word )
or
if( Search_Word.compare( word_list[z].word ) == 0 )
Last edited on
Peter87 (11236)
Case insensitive comparison

You mean "case sensitive comparison".
JLBorges (13770)
Yes! Thank you!
whitenite1 (1785)
@JLBorges

Thank you for your answer. I did forget to put in the '== 0', and now it does find the word in the list of dictionary words. I did have to first change all the words to uppercase in the word list, but that was an easy conversion. Thanks again.
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