Why is an integer being handled as a boolean?

[UberUser]

I have set up a function that is meant to return a boolean, and the input type is int to allow for invalid numbers without crashing.

bool getDone() {
	int doneIn = 0;
	cout << "Do you wish to convert another value?\n\n1: Yes\t2: No\n\nSelection: ";
	cin >> doneIn;
	if (0<doneIn<3) {
		return doneIn-1;
	}
	else {
		cout << "\nInvalid selection.";
		return 1;
	}
}

The trouble is that the expression 0<doneIn<3 appears to throw the following error, even though the variable doneIn has been declared as an int:

warning: result of comparison of constant 3 with expression of type 'bool' is always true

[Ganado]

if (0 < doneIn < 3) {

This is evaluated as (0 < doneIn) < 3.

which is either evaluated as (true) < 3, or (false) < 3, (Which will always be true in this situation).

You want to do: if (0 < doneIn && doneIn < 3)

[UberUser]

Thank you :)
I can see how it would parse it as you described, and utilizing your suggestion has resolved the issue.