generating basic sequence number

[wowisay]

i want to generate a number with n digits and all digits being same
eg the number can be 22 88888 44444 3333

but this block of code

#include <iostream>
#include<math.h>
using namespace std;

int main()
{
long long a=0,j=0,e=3;
int c=6;

for(int i=j;i<c;i++){

a=a+pow(10,i-j)*e;

cout<<a<<endl;

}
return 0;
}



produces output

333331

instead of 333333

Can anyone point out the silly mistake i am doing ?


PS: I Know the above code can be simplified but my usage requires it as it is , so please help me in this block only

[Duthomhas]

Watch your 0th power. (Eliminate it.)

[jonnin]

Hold on, the code he has seems to work perfectly for me (unchanged).
OP, recompile it and test again.

10 to the 0 = 1 * 3 = 3, 0+3 = 3, a = 3 on that iteration.

and requirements that force you to use this are terrible. at the very least getting rid of the pow() would be good. And a little creativity would make it O(1) ish. I mean, 111 * 3 is 333. 111*9 is 999. The function could be reduced to return X*Y (or at worst, x*lookup[y]).

[Duthomhas]

Oops, I mis-read it. I should have paid attention. Sorry. :-\

[homy18]

#include <iostream>
#include <math.h>
using namespace std;

int main()
{
    long long a=0,j=0,e=3;
    int c=6;

    for(int i=j;i<c;i++){

        a=a+pow(10,i-j)*e;

       cout<<a<<endl;

    }
    return 0;
}

The code works properly. No way to reproduce '333331 '.

[wowisay]

thankyou everyone , that was a compiler issue