how to pass a templated function as argument?

[nuderobmonkey]

I'm playing a bit around with function pointers. Here I tried to implement a simple generic sorting algorithm where a function should been passed for evaluating the the comparison. But I couldn't get it to work.

#include <iostream>
#include <list>

template <typename T>
bool (*fct)(T a, T b);

template <typename Itr, typename T>
void sort( Itr begin, Itr end, fct<T> cmp ) // here I need help
{   
    for( auto i = begin; i != end; ++i)
    {
        for( auto  k = i; k != end; ++k)
        {
            if( cmp(*k,*i) ) continue;
            auto tmp = *k;
            *k = *i;
            *i = tmp;
        }
    }
}

int main()
{
    std::list<int> l = { 1, 3 , 6, 2, 0};
    
    sort( l.begin(), l.end(), [](int a,int b)->bool{return a<b;} );
    
    for( auto item : l) std::cout << item;
}

Thanks for help.

[tpb]

It's simpler than you have it.

#include <iostream>
#include <list>

template <typename Itr, typename Cmp>
void sort(Itr begin, Itr end, Cmp cmp)
{
    for (auto i = begin; i != end; ++i)
        for (auto j = i; j != end; ++j)
            if (!cmp(*j, *i))
                std::swap(*j, *i);
}

int main()
{
    std::list<int> l = { 1, 3 , 6, 2, 0};
    
    sort(l.begin(), l.end(), [](int a,int b)->bool{return a<b;} );
    
    for (auto item : l) std::cout << item;
}