c++ problem
#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
int i =8,x=3;
switch (i % 2 ? 0:1)
{
case 0: x/=2;
case 1: x+=3;
case 2: x*=4;
}
cout<<"x = "<<x;
return 0;
}
#include<iomanip>
using namespace std;
int main()
{
int i =8,x=3;
switch (i % 2 ? 0:1)
{
case 0: x/=2;
case 1: x+=3;
case 2: x*=4;
}
cout<<"x = "<<x;
return 0;
}
i % 2 evaluates as 0 ...... which translates to boolean false ...
... which means that the result of the ternary expression
i % 2 ? 0 : 1 is the latter of the two options, namely 1.So the switch does case 1: that is, it adds 3 to x, making x become 6.
THEN
it drops through to the next case 2 (because there was no
break; in between) ...... multiplies x by 4 ...
... making x become 24.
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