Problem with overloading addition operator

bdh333 (2)
I have a class, largeIntegers, that stores large numbers in an integer array as single digits and i am trying to overload the addition operator to add the two numbers, digit by digit but i can't get it to work.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
 
largeIntegers operator+(const largeIntegers& large) const//overloads addition operators for addition of two large numbers
             {
                           largeIntegers tempInt;
                           
                           for(int i = 0; i < large.digits; i++)
                           {
                                   tempInt.number[i] = number[i] + large.number[i];
                                   if(tempInt.number[i] >= 10)
                                   {
                                                        tempInt.number[i] -= 10;
                                                        tempInt.number[i + 1] += 1;
                                   } 
                           }
                           
                           return tempInt;
             }


Thanks.
coolProgramer5 (193)
Why are you trying to overload them just to add them?
bdh333 (2)
yes so in main you could just have instance1 + instance2 and get the summation of the two large numbers. btw the digits of the numbers have been fed into the array backwards so addition would be easier
jsmith (5804)
Look at line 7, and consider what it does to the value if you've carried a '1' from the
previous addition.

Topic archived. No new replies allowed.