Overloading same operator multiple times

[NPcomplete]

Hi, I just wanted to know how overloading same operator multiple times works and how does the compiler know which overloaded definition is called in.
P.S: Couldn't find anything on google.

Thank you!

[MiiNiPaa]

how overloading same operator multiple times works

As with any function. Operators are just syntax sugar for function calls.

So if you have something like

foo x;
bar y;
x + y;

Compiler would look for function named operator+ which can take arguments of type foo and bar.

[JLBorges]

An overloaded operator is a function (albeit with a special syntax).
The rules for function overload resolution apply.

See: http://en.cppreference.com/w/cpp/language/overload_resolution
Note: see 'Call to an overloaded operator' on how the set of candidate functions is formed.

[MiiNiPaa]

@JLBorges: you have a stray apostrophe at the end of the link.

[JLBorges]

Thanks. Removing it now.

[NPcomplete]

Thank You very much!