Using Complex Numbers for Circles and Right Triangles.

[CATCH3624]

Hello People...HAPPY BELATED THANKSGIVING...I'm having problems trying to get this Complex program to do certain functions...Here is my problems...
* Suppose that each complex number represent a point on XY-plane*Add one function to the complex class that calculate the distance from one point to another point* double distance( Complex a, Complex b );*Add the prototype in header file and function definition in source file*Write a driver program(contain main()function) that ask user to enter three complex numbers a,b,c( real and img part for each number)*Decide if the three point form a right triangle*Decide if the three points are on a same circle centered at (0,0)*Print a message that states if the three numbers will form a right triangle or on one same circle or neither...This is what I have so far...

#include <iostream> // Directive for iostream library.
using namespace std; //Namespace is a collection of identifiers in the standard library.
class Complex // Type Object
{                   
	double real;
	double img;
public:       // Constructors
	Complex(double a=0, double b=0); 
	void set_real(double r);
	void set_img(double g);
	double get_real();
	double get_img();
	void print();
	Complex plus(Complex c);
	Complex minus(Complex c);
	Complex mul(Complex c);
	Complex div(Complex c);
};
#include "Complex.h"

Complex::Complex(double r, double g)  
{
	real = r;
	img = g;
}
void Complex::set_real(double r) {real = r;} // Complex Member Functions
void Complex::set_img(double g) {img = g;}
double Complex::get_real() {return real;}
double Complex::get_img() {return img;}

void Complex::print()
{
	cout<< real<<"+"<<img<<"i";
	cout<< "(" <<real<<", "<<img<<")"; 
}
Complex Complex::plus(Complex c)  // Complex Operator
{
	Complex x;
	x.real = real + c.real;
	x.img = img + c.img;
	return x;
}
Complex Complex::minus(Complex c) // Complex Operator
{
	Complex x;
	x.real = real - c.real;
	x.img = img - c.img;
	return x;
}
Complex Complex::mul(Complex c) // Complex Operator
{
	Complex x;
	x.real = real * c.real -img * c.img;
	x.img = img * c.real + real * c.img;
	return x;
}
Complex Complex::div(Complex c) // Complex Operator
{
	Complex x;
	double temp = c.real * c.real + c.img * c.img;
	x.real = (real * c.real + img * c.img) / temp;
	x.img = (img * c.real - real * c.img) / temp;
	return x;
}
#include "Complex.h"

 int main()
{
 Complex total;
 Complex *ptr;
 double r, g;
 int num, i;
 cout << "\n Enter how many numbers of complex numbers\n";
	 cin >> num;
 ptr = new Complex[num];
 for ( i = 0; i < num; i++)
 {
	 cout <<"Enter the pair of numbers for "<<i+1<<"th number\n";
	 cin>>r>>g;
	 ptr[i].set_real (r);
	 ptr[i].set_img (g);
	 total = total = total.plus (ptr[i]);
 }
 cout<<"The total is ";
 total.print();
 cout<<endl;
 return 0;
 } 

[kbw]

Your arithmetic requires code like:
Complex c1, c2;
//...
c1.plus(c2);

Whereas, you might want to write
Complex c3 = c1 + c2;

So you really should have operators +, - and so on.

Those are points of style and may not be important here, but something to think about non the less.

They form a right-angle triangle if one angle of the formed triangle is 90 degrees.

They lie on the same radius if the distance to the centre (0,0) is the same. Pythagoras' theorem comes to mind.

[CATCH3624]

thanks that's great but how can I apply this when the input from the user will be a set of numbers whereas I must take and then calculate whether it's a right triangle or on one same circle (0,0) or neither???

[tition]

Four different complex numbers a,b,c,d lie on a cirlce if and only if

( (a-d)/(b-d) ) * ((b-c)/(a-c))

is a real number (i.e. if its imaginary part equals zero).

Hope this helps!


[Edit:] Or they lie on a line (line = circle of infinite radius). Three complex points a,b,c lie on a line when (a-b)/(a-c) is a real number.