Outputting new lines for each 10

[spazamatic2]

The user is asked to type in a character and a number. The character will then be printed out that many times, but only 10 characters per line. If first they type in 7 and then the next time around they type in 12, only 3 can go on one line then 9 on the next. I'm not sure how to manipulate my program to do this.

while ( number > 0)
{
cout << endl;
cout << "please enter a positive integer" << endl;
cin >> number;
if (number > 0)
{
cout << "please enter a character" << endl;
cin >> character;
cout << endl;



for (int i = 1; i <= number; i++)
{
cout << character;
if (i % 10 == 0)
cout << endl;
}
}

[firedraco]

You will need to have a number that is used throughout the entire while loop. Try going from that and see what you get.

[spazamatic2]

Where would I put this in the while loop so that it doesn't mess up the rest of the program. And do I need to declare a different variable that is set equal to 10?

[chrisname]

No, you would have one variable that would be 0. For every character you print, you add one to the variable. When the variable == 10, you print a newline, then carry on.

[mbittel12]

Tested and it works, please study it!! YOU MUST LEARN FROM THIS:

#include <iostream>

using namespace std;

int main()
{
     int number = 0, count = 0;
     char character;

     cout << "Please enter a positive integer and a character: ";
     cin >> number >> character;

     if(number > 0)
     {  
          for(int i = 1; i <= number; i++)
          {
               cout << character;
               count++;

               if(count == 10)
               {
                    cout << endl;
                    count = 0;
               }
                    
          }
     }
}