how to control how many characters are printed per line

[nrose]

my prof wants us to write a program that accepts positive integers and a character input then when the program outputs what you entered there are only 10 characters per line.
this is what i have so far

#include <iostream>

using namespace std;

int main() {

int num;
char character;
cout << "give me a positive integer ";
cin >> num;
cout << " give me a character";
cin>> character;

for (int j=0; j<num; j=j+1)
{
cout << character;
}
cout << endl;


return 0;
}

if i input 15 and b
it outputs
bbbbbbbbbbbbbbb

i need it to output
bbbbbbbbbb
bbbbb


can anyone help if been trolling forum afte forum trying to figure it out

[nrose]

i have figured more of it out but im not sure if it is right?
using namespace std;

int main()

{
char character;
int num;
int x= 9;


cout << "Enter a positive integer: " << endl;
cin >> num;
cout << "Enter a character: " << endl;
cin >> character;
cout << "The positive integer entered was " << num << endl;
cout << "The character entered is " << character << endl;



for (int j=0; j<x; j++)
{
cout << character;
}


if (num> 0)
{
while (num> 0)
{
cout << character << endl;
num= num-1;
}


}

else cout << " Thats an incorrect number!" << endl;

return 0;
}

now it outputs
bbbbbbbbbb
b
b
b
b
b
b
b
b
b
b
b
b
b
b

[bluezor]

Use a for() loop. If the line count (j in your case) is 9, 18, 27, etc (10th character in a line), print a new line.
Hint: use modulo

[nrose]

ok im close to having my program print out the right thing now the only problem is that it prints out like
b
bbbbbbbbbb
bbbb

how do i get that first b to fall into place correctly

my code now looks like

int main() 

{
  
  int num;
  char character;
  cout << "give me a positive integer ";
  cin >> num;
  cout << " give me a character";
  cin>> character;

if (num > 0)
{
    for (int N = 0; N < num; N++)
    {
        std::cout << character;
        if (N % 10 == 0) 
            std::cout << endl;
    }
}

                      else cout << "that isnt a valid integer" << endl;
    

  return 0;
}

[bluezor]

Change N to 1 and N <= num.
0 modulo 0 is always 0.

[nrose]

already got it running thanks for your help