function overloading

[karthik8913]

this is what i did in c++ while overloading a function

int add(void); //function call with void as argument
int add(); //passing nothing

i know these two lines are perfectly valid. but how? please tell me difference between (void) and ().how compiler is distinguishing between these two arguments and allows overloading the function?

[shacktar]

The function declarations int add(void); and int add(); are equivalent. They both mean "there is a function, called add, returning an int that takes no parameters".

how compiler is distinguishing between these two arguments and allows overloading the function?

It doesn't. The following will produce a compiler error because the function already exists:

int add()
{
   return 0;
}

int add(void)
{
   return -1;
}

The following code will not produce compiler errors:

int add();
int add(void);

because they are simply declarations (and you can have multiples of the same declaration). However, you cannot have multiple definitions.

[karthik8913]

cool!....