Yes/No programming question

[dukereuchre]

Alright so i have this code i made, and i want to ask if you are sure that is what you want but i dont know how. here is the code. ill bold the part i need help in

// Michael DeGray Wednsday September 23, 2009
#include <iostream>

using namespace std;
using std::cout;
using std::cin;
using std::endl;

int main()
{
int numb1;
int numb2;
int numb3;
int numb4;
int sum1;
int sum2;
char Y;
char N;


cout << "This program will take two numbers and add them, then it will take two seperate number add them and compaire the two. " << endl << "\nPlease input your first number.\n"; // promts for user input
cin >> numb1; // stores inputed number as numb1

cout << "Please input the number to be added to the previous number.\n"; // promts for user input
cin >> numb2; // stores inputed number as numb2

cout << "The first equation is " << numb1 << " + " << numb2 << endl << "Is this correct? Y/N\n"; // shows the equation for the first set of inputed numbers
cin >> Y;
if Y
sum1 = ((numb1 + numb2));

cout << "The answer to the first equation is " << sum1 << endl; // shows answer to first equation

cout << endl << "Please input the first number of the second equation.\n"; // asks for user input
cin >> numb3; // stores inputed number as numb3

cout << "Please input the number to be added to the previous number.\n"; // asks for user input
cin >> numb4; // stores inputed number as numb4

cout << "The second equation is " << numb3 << " + " << numb4 << endl; // shows equation for the second set of inputed numbers

sum2 = ((numb3 + numb4));

cout << "The answer to the second equation is " << sum2 << endl << endl; // shows answer to second quation

if ( sum1 == sum2 ) // Is the two numbers are equal display the following
cout << sum1 << " == " << sum2 << endl;

if ( sum1 != sum2 ) // if the two numbers are not equal display the following
cout << sum1 << " != " << sum2 << endl;

if ( sum1 < sum2 )
cout << sum1 << " < " << sum2 << endl;

if ( sum1 > sum2 )
cout << sum1 << " > " << sum2 << endl;

if ( sum1 <= sum2 )
cout << sum1 << " <= " << sum2 << endl;

if ( sum1 >= sum2 )
cout << sum1 << " >= " << sum2 << endl;

return 0;
}

Now if the user types Y then it contuines with the program but if they press N it will ask them for 2 numbers again. how would i do this? thanks in advance

EDIT: for some spelling errors (there are probably more i missed but i think it's readable)

[shriek]

didn't quite get you when you said continue with program ...how should the program look?
btw the if statement should have something like if (y) ...parenthesis are required..

[Zhuge]

You would need to use a loop of some sort.

[Bv202]

Hi,

1) You don't need to include the whole std namespace when you're including some parts of it.
2) A variable name has nothing to do with user input. You're storing the user input in a variable of type char with the name "Y" and assumes the user really typed Y. But the user can also type in other things.

You could use a char variable, then check what the user did input. You will need to use a while loop to ask for 2 numbers again. To use yes/no, you will need a boolean variable.

Example:

int num1 = 0;
int num2 = 0;
char input = "";
bool correct = false;

while (!correct)
{
     cout << endl << "Enter number 1: ";
     cin >> num1;
     cout << endl << "Enter number 2: ";
     cin >> num2;
     cout << endl << "Did did enter " << num1 << " and " << num2 << ". Is this correct? (Y/N)";
     cin >> input;

     switch(input)
     {
          case 'Y':
             correct = true; // Now the loop will stop
          case 'N':
             correct = false; // As correct is still false, it will repeat the whole while-loop
     }
}

3) You don't need parenthesis here:
sum2 = ((numb3 + numb4));
It will compile, but it's useless.

4) Use code-tags to post your code please; that's much more readable =)

[dukereuchre]

Thanks so much! I'm new to programming so im sorry if its hard to read :( but i reall appricate all the help! Thanks again!

How do i use code-tags?

[Bv202]

Just put your code in [code ][/ code] (without spaces) to use code-tags.