float gets unwillingly outputted as int - using Operator Overloading

Grashek (1)
Hey Guys,

I fooled a bit around with the Operator Overloading and stumbled across something I don't understand yet. I've uploaded this mini program here (http://ideone.com/Wu2Vh1) so you can see and execute it.

Now I have a method that calculates my float c from (a²*b² = c²) If I output it straight from that method, it will show the correct c including all decimal places.

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class RightTriangle : public Shape
{
  public:
  RightTriangle(float a, float b, int x, int y) : a_(a), b_(b), Shape(x, y)
  {
  }

  friend std::ostream& operator<< (std::ostream& stream, RightTriangle& test_class);

  int Hypothenuse()
  {
    float c = 0.0f;
    c = std::sqrt(a_*a_ + b_*b_);

    std::cout << "thats the standard c = " << c << std::endl;
    return c;
  }



If I output it with my operator overloading function, the compiler interprets the "c" as an integer variable it seems, because every decimal place gets cut.

This happens here:

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 std::ostream& operator<< (std::ostream& os, RightTriangle& test_class)
 {
   std::cout << "Thats the overloaded c: " << test_class.Hypothenuse() << std::endl;
   return os;
 }


int main()
{
  RightTriangle *test_class = new RightTriangle(2.0f, 3.0f, 4.0f, 5.0f);
  std::cout << *test_class;


Output will look like this: 
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thats the standard c = 3.60555
Thats the overloaded c: 3



I don't really understand why the compiler does so. Would be great if you could help me out.

Edit: Solved - trivial, ofc I have to declare my method as float, if I want it to return a float.

TL;DR float c will be outputted as if it was an int, while using Operator Overloading - Help me to output it with all its decimal places
Last edited on
Caligulaminus (201)
int Hypothenuse() returns an int.
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