Class Stack

[qi11qi11]

I got a problem with a program for Port Cargo Retrieval question.
I need to create a 10 x 10 stack , 10 companies, 1 stack for 1 company. and would be able to take out the particular cargo when chosen.
This problem must be solved by using class stack.


#include <iostream>
#include <stack>
#include <string>
#include <vector>
using namespace std;


template<typename T>
void printstack(T &x)
{
while(!x.empty())
{
cout<<x.top()<<" ";
x.pop();
}
}

class mycargo{

public:
string name;
string items;
string weight;
};

int main(){
stack<mycargo>coyA;
stack<mycargo>coyB;
stack<mycargo>coyC;
stack<mycargo>coyD;
stack<mycargo>coyE;
stack<mycargo>coyF;
stack<mycargo>coyG;
stack<mycargo>coyH;
stack<mycargo>coyI;
stack<mycargo>coyJ;
stack<mycargo>tempco;
stack<string>tempstack;

mycargo temp;
mycargo temp2;
mycargo temp3;
mycargo temp4;
mycargo temp5;

mycargo C1;
mycargo C2;
mycargo C3;
mycargo C4;
mycargo C5;
mycargo C6;
mycargo C7;
mycargo C8;
mycargo C9;
mycargo C10;
C1.name = "Tan";
C1.items= "apparel";
C1.weight= "100 tonnes";
C2.name = "Wong";
C2.items= "watches";
C2.weight= "75 tonnes";
C3.name = "Lim";
C3.items= "food";
C3.weight= "55 tonnes";
C4.name = "Chua";
C4.items= "clothes";
C4.weight= "25 tonnes";
C5.name = "hilton";
C5.items= "drinks";
C5.weight= "30 tonnes";
coyA.push(C4);
coyA.push(C3);
coyA.push(C2);
coyA.push(C1);
string company,name_temp;
cout<<"company: ";
cin>>company;
if(company=="coyA"){
cout<<"Name of container: ";
cin>>name_temp;
temp=coyA.top();
tempstack.push(name_temp);
cout<<tempstack.top();
if(name_temp==tempstack.top()){


tempco.push(coyA.top());
cout<<temp.name;
cout<<temp.items;
cout<<temp.weight;
coyA.pop();
}








}
/*while(!coyA.empty()){
temp=coyA.top();
cout<<temp.name<<endl;
cout<<temp.items<<endl;
cout<<temp.weight;
coyA.pop();



}*/

}
no idea hw to continue

[kbw]

You really should post your question in one forum.

If you enter the values coyA and Tan when prompted, it prints your output. So it works, right?

[qi11qi11]

well, it does print. But, it prints no matter what input i type for name_temp. so,
name_temp==tempstack.top() doesn't really compare at all.