function template specialization

R0mai (730)
Hi,

Is it possible to specialize templated function with templated templates?

I'm not sure if it's possible, and if yes what is the proper syntax.

I would imagine it something like this :

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template<class T>
class bar {};
template<class T>
class baz {};

template<class C1, class C2>
C1 foo( const C2& );

template<>
template<class T>
bar<T> foo< bar<T>, baz<T> >( const baz<T>& ) {
	//....
}


Last edited on
guestgulkan (2942)
I don't think you can specialise template functions that way. You have to use function overloading.
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template<typename T>
bar<T> foo( const baz<T>& bz )
{
     //......
 }
smilodon (155)
yes it is, but remember to put in a function name.
R0mai (730)
I don't think you can specialise template functions that way. You have to use function overloading.


I tought of that, but I need to use two type of overloaded version of this func, with the only difference in the return value, like:

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template<typename T>
bar<T> foo( const baz<T>& bz ) {
     //......
}

template<typename T>
bar_baz<T> foo( const baz<T>& bz ) {
     //......
}

bar_baz<int> h = foo( baz<int>() ); //ambigouos call


I tought it would be nice to use the same function name for both, but than it seems I'm gonna have to use functions with different names :)

smilodon (155)
can you overload return types?
Zhuge (4664)
No, you can't overload on return types.
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