Calling a string in one function, into a new function

MJGilbert (48)
Hi guys, how would I call a string that sits within a switch loop in the main function, into a separate function?

Like this:
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void statistics()
{
    cout << "Here are the statistics for your entry: " << endl;
    cout << "\nThe size of your entry is " << s.length() << " characters." << endl;
}


I am calling string s from this:
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  switch (toupper(myChoice))
        {
            case 'A': cin.ignore();
                      cout <<"\nPlease enter your text: ";
                      getline(cin, s);
                      cout << "\nYou entered: " << s << endl;
                      cout << endl << "(Press Enter key to continue)\n" << endl;
                      cin.ignore(numeric_limits<streamsize>::max(), '\n');
                      myMenu();
                      break;


^^^^^^ That is the main function.

Thanks a bunch guys!
Mats (1398)
You need to give the function an argument and then pass the string to it. This sounds complicated, but luckily, it really isn't! 
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void statistics(string statsx) //That thing in the brackets is an argument. 
//It means whenever we call statistics() we give it a string inside those brackets. 
{
    cout << "Here are the statistics for your entry: " << endl;
    cout << "\nThe size of your entry is " << statsx.length() << " characters." << endl;
    
}

int main()
{
    string s = "this is some data in a string."; 
    statistics(s); 
    return 0;
}


If you didn't quite understand that, here is another example with something simpler: 
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#include <iostream>

using std::cout;

void n(int x)
{
    cout << x;
}

int main()
{
    int y = 5;
    n(y);
    return 0;
}


You can read more here: http://www.cplusplus.com/doc/tutorial/functions/
MJGilbert (48)
By George, you've got it! That was super simple, I realize now how simply confusing it is sometimes lol... I really appreciate the help, it means a lot!

Thanks again!
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