how to do vice versa operation? C

Giorgi Gvimradze (5)
i wrote a program which can calculate numerical meaning of a word i type. now i want to type a number and get all possible choices of word list, how is it possible? here is my prog in C language:

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#include <stdio.h >

int main ()
{
	char string1[20];


	char a='a', b='b', g='g', X='X', i='i', H='H', V='V', d='d', e='e', v='v', z='z', E='E', T='T', I='I', k='k', l='l', m='m', n='n', o='o', p='p', j='j', r='r', s='s', t='t', u='u', f='f', q='q', R='R', y='y', S='S', w='w', C='C', W='W', x='x', h='h', c='c', J='J', Z='Z';


	
	
	int rigi;
	int sum;

	printf (" my word is:\n");
	scanf( "%19s ", string1);


		 
	 sum=0;
	   for (rigi = 0; string1[rigi] !='\0'; rigi++)
    {

	if (string1[rigi]==a ) {sum= sum +1;} else
	if (string1[rigi]==b ) {sum= sum +2;} else
	if (string1[rigi]==g ) {sum= sum +3;} else
	if (string1[rigi]==d ) {sum= sum +4;} else
	if (string1[rigi]==e ) {sum= sum +5;} else
	if (string1[rigi]==v ) {sum= sum +6;} else
	if (string1[rigi]==z ) {sum= sum +7;} else
	if (string1[rigi]==E ) {sum= sum +8;} else
	if (string1[rigi]==T ) {sum= sum +9;} else
	if (string1[rigi]==i ) {sum= sum +10;} else 
	if (string1[rigi]==k ) {sum= sum +20;} else
	if (string1[rigi]==l ) {sum= sum +30;} else
	if (string1[rigi]==m ) {sum= sum +40;} else
	if (string1[rigi]==n ) {sum= sum +50;} else
	if (string1[rigi]==I ) {sum= sum +60;} else
	if (string1[rigi]==o ) {sum= sum +70;} else
	if (string1[rigi]==p ) {sum= sum +80;} else
	if (string1[rigi]==J ) {sum= sum +90;} else
	if (string1[rigi]==r ) {sum= sum +100;} else
	if (string1[rigi]==s ) {sum= sum +200;} else
	if (string1[rigi]==t ) {sum= sum +300;} else
	if (string1[rigi]==V ) {sum= sum +400;} else
	if (string1[rigi]==u ) {sum= sum +0;} else
	if (string1[rigi]==f ) {sum= sum +500;} else
	if (string1[rigi]==q ) {sum= sum +600;} else
	if (string1[rigi]==R ) {sum= sum +700;} else 
	if (string1[rigi]==y ) {sum= sum +800;} else
	if (string1[rigi]==S ) {sum= sum +900;} else
	if (string1[rigi]==C ) {sum= sum +1000;} else
	if (string1[rigi]==c ) {sum= sum +2000;} else
	if (string1[rigi]==Z ) {sum= sum +3000;} else
	if (string1[rigi]==w ) {sum= sum +4000;} else
	if (string1[rigi]==W ) {sum= sum +5000;} else
	if (string1[rigi]==x ) {sum= sum +6000;} else
	if (string1[rigi]==X ) {sum= sum +7000;} else
	if (string1[rigi]==j ) {sum= sum +8000;} else
	if (string1[rigi]==h ) {sum= sum +9000;} else
	if (string1[rigi]==H ) {sum= sum +1000;} else
	{sum=0;}

	   }

	printf ("%d\n" , sum);
	return 0;

}


Last edited on
MiiNiPaa (8886)
You can make a dictionary of words and their numerical meaning. After that you should pick those which have needed meaning.

In C++ I would use std::map<unsigned int, std::vector<std::string>>
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