Need help with ARRAYS please!

[Yestsuae123]

I have the majority of this program written but I see flaw in it the last section after the do while statement i think needs to be another array probably close to the one on top but I just cant seem to get it. If anyone could help that would be great. The program asks the user several times for you to enter a positive integer up until you enter -1 to exit the loop. Then lets say you do four inputs and on the fifth prompt you enter -1. This would mean an output would show 4 integers entered, once you enter -1 the program then asks you to enter a string as many times equal to how many integers you just entered, example:

"please enter a positive integer (-1 to exit): 1
"please enter a positive integer (-1 to exit): 2
"please enter a positive integer (-1 to exit): 3
"please enter a positive integer (-1 to exit): 4
"please enter a positive integer (-1 to exit): -1
"please enter string: hello
"please enter string: to
"please enter string: you
"please enter string: guys

The output for this should be:

1 : : hello
2 : : to
3 : : you
4 : : guys

but instead when the code is compiled and the input stored the output is this:

1 : : guys
2 : : guys
3 : : guys
4 : : guys

The string part of this code I want to become an array so as to make work the right way but I am not sure how. Here is my code with comments.

#include <iostream>
#include <string>
using namespace std;
int main()
{
	string word;
	int integer[100];
	int integerVar=-1;

	do
	{
		integerVar = integerVar + 1;
		if (integerVar > 100)
		{
			cout << "Highest possible amount is 100";
			break;
		}
		cout << "Enter a positive integer (-1 to exit): ";
		cin >> integer[integerVar];
		
	}
	while (integer[integerVar] != -1);
	
	cin.ignore(); // I want an array for 'word' to make the expected output just need a lil help
	
	string word[100];
	int wordVar = wordVar + 1;
	while (word[wordVar] < integer[integerVar])
	{
		cout << "Enter a string: ";
		cin >> word[wordVar];
	}
}

[ToniAz]

int wordVar = wordVar + 1; is outside the "string loop". Do the same thing you did inside the "number loop" and it should work fine.

cin.ignore(); // I want an array for 'word' to make the expected output just need a lil help

Didn't understand this. I don't know if you're looking for this

string str;
cin >> str;
word[wordVar] = str;

The second loop should iterate as many times as the number of inputted numbers. Therefore, you need to declare a counter that keeps track of how many integers have been inputted.


Was giving me weird errors, never do this: string string;

This means nothing: int wordVar = wordVar + 1;

[soranz]

Line 27 you are declaring wordVar and using it at the same time ?

Line 28 - that comparison is meaningless...

//note that integer[integerVar] == -1 so it's probably not the comparison you want
//word[wordVar] == "some string" and not an integer  

//untested
int wordVar = -1;
while (wordVar < integerVar) 
{
        wordVar = wordVar + 1;  //do u mean for this inside the loop like earlier?
	cout << "Enter a string: ";
	cin >> word[wordVar];
}

[Yestsuae123]

ok guys I apologize for the errors I did not mean to string a string I meant string word and all I am trying to do is make answers "enter a string" show up just like they did in the first output at the top of the forum post and soranz it is possible thats what i wanted.

[ToniAz]

How about this?

#include <iostream>
#include <string>


using namespace std;


int main()
{
	int    a[100];
	string s[100];
	int count = 0;
	do
	{
	    cout << "\nEnter a number: ";
	    cin >> a[count++];
	} while (count < 100 && a[count-1] != -1);

	int i;
	for (i = 0; i < count - 1; i++) // you will eventually enter -1 
	{
	    cout << "\nEnter a word: ";
	    cin >> s[i];
	}

	for (i = 0; i < count - 1; i++)
	{
	    cout << a[i] << " :: " << s[i] << endl;
	}

	return 0;
}

Enter a number: 94

Enter a number: 96

Enter a number: -1

Enter a word: ninetyfour

Enter a word: ninetysix
94 :: ninetyfour
96 :: ninetysix