Ignore all input after the first char

[TheDudiful]

This is my code:

int main()
{
    char ansPlay;
    cout<<"Welcome! Would you like to play a game of Roulette? \n<Y>es or <N>o"<<endl;
    while(1)
    {
        cin>>ansPlay;
        
        if(ansPlay == 'N' || ansPlay == 'n')
        {
            cout<<"Too bad. See you next time.";
            cin.get();
            return 0;
        }
        else if(ansPlay == 'Y' || ansPlay == 'y')
        {
            cout<<"Wonderful! Let's Play!";
            break;
        }
        else
        {
            cout<<"The answer needs to be <Y>es or <N>o. Try again."<<endl;
        }
    }
    cin.get();
    return 0;
}

Now, when I give "yes" or "no" or anything starting with an "n" or a "y" it works just fine. But if I enter for example: "asdf", it gives the output: "The answer needs to be <Y>es or <N>o. Try again." four times, once for every character. So I was wondering if there's a way to discard all characters that come after the first? Or if this is not the right way to do it, how should it be done?
Thanks in advance.

[omeraslam]

instead of char ansPlay use string ansPlay and use ansPlay[0] == 'Y' in if conditions.
include string header file if it gives error

[Lowest0ne]

But then you have an entire string object in memory. Just use cin.sync()

cin >> ansPlay;
cin.sync();

[TheDudiful]

Thanks omeraslam and LowestOne for responding. LowestOne, I used your suggestion and it worked, thank you very much.

[Peter87]

Note that cin.sync() work different on different compilers.

Isn't it enough to discard all input until the end of the line? You can do that by using ignore:
cin.ignore(numeric_limits<streamsize>::max(), '\n');