Char is not outputting what it is supposed to.

Gregory Sakas (72)
This program:
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int x, y;
char grid[16][16];
	
for(x=0;x<16;x++)
	grid[x][0] = '.';
for(y=0;y<16;y++)
	grid[0][y] = '.';
for(x=0;x<26;x++)
	grid[x][15] = '.';
for(y=0;y<16;y++)
	grid[15][y] = '.';
for(x=1,y=1;x<15,y<15;x++,y++)
	grid[x][y] = ' ';

for(x=0;x<16;x++)
{
	for(y=0;y<16;y++)
		cout << grid[x][y];
	cout << endl;
}

should create a box of periods surrounding space, but I get this instead:

................
. .
. \200
\340.
.\357\340 \313o\340\217K&\340.
.\367\377\277 \350\366\377\277r<\340.
. \367\377.
.\367\377\277l\367 \277.
. .
. .
. .
. 	.
.\340\217<\367\377 l\367\377.
. .
.	\300\340\217 \342.
.\274 .
................
Catfish (666)
Line 8 in your code, x<26?
vlad from moscow (6539)
I see a typo

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for(x=0;x<26;x++)
	grid[x][15] = '.';

you array has only 16 rows not 26.

To escape such a typo it is better to set dimensions of an array with constants.

For example

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const size_t N = 16;

char grid[N][N];

for ( size_t i = 0; i < N; i++ )
{
   for ( size_t j = 0; j < N; j++ )
   {
      if ( i == 0 || j == 0 || i == N - 1 || j == N - 1 ) grid[i][j] = '.';
      else grid[i][j] = ' ';
   }
}


for( size_t i = 0; i < N; i++ )
{
   for ( size_t j = 0; j < N; j++ )
   {
      cout << grid[i][j];
   }
   cout << endl;
}


I have not tested this code but hope it is correct.
Last edited on
Gregory Sakas (72)
The typo was not the problem, I am still getting:

................
. .
. \200
\340.
.\357\340 \313o\340\217K&\340.
.\367\377\277 \350\366\377\277r<\340.
. \367\377.
.\367\377\277l\367 \277.
. .
. .
. .
. 	.
.\340\217<\367\377 l\367\377.
. .
.	\300\340\217 \342.
.\274 .
................
vlad from moscow (6539)
change the loop

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for(x=1,y=1;x<15,y<15;x++,y++)
	grid[x][y] = ' ';

to

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for ( x = 1; x < 15; x ++ )
{
   for ( y = 1; y < 15; y++ )
   {
      grid[x][y] = ' ';
   }
}

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