printing a pattern

[kakashi316]

for an assignment i have to use nested for loops to print this:
*
***
*****
*******
*********
***********
*************

this is the code i have:
#include<iostream>
using namespace std;
int main()
{
for(int i=1; i<=7; i++)
{
for(int j=1; i<=13; i++)
{
if (j>=i&&j>=10-i)
cout<<static_cast<char>(6);
else
cout<<" ";
}
cout<<endl;
}
return 0;
}

note:the symbol is supposed to be a spade,but i used a star for example.
the code isnt close to right,any help is appreciated.

[jsmith]

There are 7 lines of output. So I understand your outer for loop.
On the 1st line of output there is 1 star. On the 2nd there are 3. On the 3rd there are 5. So it seems like the Nth line of output contains 2N - 1 stars. You just need to change the terminating condition on your inner for loop and get rid of the if() check.

[kakashi316]

Im still having trouble with this code

the new code with the recent suggestion:
#include<iostream>
using namespace std;
int main()
{
for(int i=1; i<=7; i++)
{
for(int j=1; j<=13; j++)
{
if (j<=i&&j>=2i-1)
cout<<static_cast<char>(6);
else
cout<<" ";
}
cout<<endl;
}
return 0;
}

any help is still appreciated

[jsmith]

Hint: your inner for loop's terminating condition should be a function of i.

The purpose of your inner for loop is to print some number of stars on a line.
The number of stars it needs to print is 2N - 1, where N is the line number.
In your code, i is the line number.

Change the body of your innermost for loop to

cout << "*";

[kakashi316]

am i any closer with this:
#include<iostream>
using namespace std;
int main()
{
for(int i=1; i<=7; i++)
{
for(int j=1; j<=13; 2i-1)
{
if (j>=i&&j<=1)
cout<<static_cast<char>(6);
else
cout<<" ";
}
cout<<endl;
}
return 0;
}


note:im supposed to print out a pyramid of spades its just that i used * for the purpose of illustarting the pyramid

[jsmith]

Somewhat. the 2i-1 is the terminating condition on the for loop, not the increment.

for( int j = 1; j <= 2 * i - 1; ++j )

Try that. And you need to get rid of the if-else statement and replace it with what I suggested above (you can replace the * with static_cast<char>(6) to get your spade).

[kakashi316]

ok,changed the code again:
#include<iostream>
using namespace std;
int main()
{
for(int i=1; i<=7; i++)
{
for(int j=1; j<=2*i-1; ++j)
{
cout<<static_cast<char>(6);
}
cout<<endl;
}
return 0;
}

but i still get just a solid row of 13 spades.anybody know what im doing wrong.

[kakashi316]

nevermind,i got it

[simply thunder]

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