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#include <iostream>
#include "datefuns.cc"
#include <fstream>
#include <iomanip>
using namespace std;
/********************************Date to Long Date Function *******************************************************/
/*********************************Convert Date to Ordinal Form Function********************************************/
// This program will take in a date in mm dd yyyy form and convert it to an ordinal date
int ordinalForm (int month, int day, int year)
{
int ordinalDay1; // Declares the ordinal date integer
// Calculate the number of days for each month without taking into consideratoin the
// leap year
if (month == 1) // This calculates days in January
ordinalDay1 = day;
else if (month == 2) // This calculates days in February
ordinalDay1= 31 + day;
else if (month == 3) // This calculates days in March
ordinalDay1 = 59 + day;
else if (month == 4) // This calculates days in April
ordinalDay1 = 90 + day;
else if (month == 5) // This calculates days in May
ordinalDay1 = 120 + day;
else if (month == 6) // This calculates days in June
ordinalDay1 = 151 + day;
else if (month == 7) // This calculates days in July
ordinalDay1 = 181 + day;
else if (month == 8) // This calculates days in August
ordinalDay1 = 212 + day;
else if (month == 9) // This calculates days in September
ordinalDay1 = 243 + day;
else if (month == 10) // This calculates days in October
ordinalDay1 = 273 + day;
else if (month == 11) // This calculates days in November
ordinalDay1 = 304 + day;
else // This calculates days in December
ordinalDay1 = 334 + day;
// If it is a leap year then if the date is after February 28th, you would add this
if (isLeapYear (year) && (month >= 3)) // This is to say that if it is a leap year, then on or after
ordinalDay1 = ordinalDay1 +1; // the 3rd month, you add 1 day to the day of the year
// Return the ordinal date to the main function
return (ordinalDay1);
}
/*****************************************Main Function**********************************************************/
int main ()
{
ifstream inFile; // Declaration of file that holds all the information
int month; // This is the month of the year
int day; // The day of the month
int year1; // This is the year
int numberDaysChange; // This is the number of days that the original date will change
string currentLine; // The current line that is being read in
int ordinalDay1; // This is the current date in ordinal form
int ordinalDay2; // The second ordinal day after the number of days changed
int currentYear; // The length of the current year
int year2; // The year after the change in number of days
// Open up the file and test for a good open
inFile.open ("dates.txt");
if (!inFile)
{
cout << "File did not open correctly. Exiting program..." << endl;
return 1;
}
// Begin the while loop to read in the date and display it in the new format
while (inFile)
{
// Read in the month, day, year, and the number of days to add or subtract
inFile >> month >> day >> year1 >> numberDaysChange;
// Calculate the length of the current year
if (isLeapYear (year1))
currentYear = 366;
else
currentYear = 365;
// Call the function to convert the date to ordinal form
ordinalDay1 = ordinalForm (month, day, year1);
// Add numberDaysChange to the ordinal form number
ordinalDay2 = (numberDaysChange + ordinalDay1);
// Use if else statement to determine if the ordinal date forces a new year
if (ordinalDay2 > currentYear)
{
ordinalDay2 -= currentYear;
year2 = year1 + 1;
}
else if (0 < currentYear)
;
else if (ordinalDay2 < 0)
year2 = year1 -1;
// Call function in datefuns.cc to convert back to mm dd yyyy form
dayToDate (ordinalDay2, year2, month, day);
cout << ordinalDay1 << endl;
}
return 0;
}
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