Encryption

[Taboo]

a) Replace each digit with that digit plus 7.

b) Swap the first digit with the third.

c) Swap the second digit with the fourth. Then print the encrypted four-digit integer.

OK, I did the first one (I think), but I need help switching the first with the third digit and the second with the forth. Can anyone help me with this?


#include
void main()
{
cout<<"Enter a four-digit number to be encrypted:";
char a[4];
cin >> a;
int b[4];
b[0]=(int(a[2])-int('0')+7)%10;
b[1]=(int(a[3])-int('0')+7)%10;
b[2]=(int(a[0])-int('0')+7)%10;
b[3]=(int(a[1])-int('0')+7)%10;
cout<<"Encrypted number is:";
for(int i=0;i<4;i++){

}
}

[ne555]

[code] Your code goes here [/code]

char a[4];
cin >> a;

The array will end with a '\0', so you need to oversize it.

Do a swap function with an auxiliary (or use std::swap)

[Taboo]

Can you show me what that looks like?

[Taboo]

Anyone?

[visualbasi]

for swapping
int c;
c=b[0];
b[0]=b[2];
b[2]=c;
c=b[1];
b[1]=b[3];
b[3]=c;


and take the size of a 5.1 space for /0.you should declare a as: int a[5];
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