What will the i++ do in here? Easy i++?

[bigbrain]

I saw this codes from somewhere and don't really get it..
I know when i is smaller than argc, then it will keep on looping. Then if the present argv is phone number, then phone should read the present argv? I just don't see the point why we need to put i++ in argv[]? wouldn't it read next argv?

while (i<argc)
	{
		if(isphone(argv[i]))
		{
			
			phone = argv[i++];
		}
		else if (isemail(argv[i]))
		{	
			i++;
			email = argv[i++];
		}

[Athar]

No, google "post increment".

[wenqiang]

that is to say:
j=i++;
equal to

 j=i;
++i;

or

j=i;
i++;

BTW: we always say C++ , not ++C. cause Cplusplus must equal to C first.