C++ patterns

[josh84]

Any help on how to get this pattern printed?

**********
*********
********
*******
******
*****
****
***
**
*

The code I have prints it on the inverted side.

#include<iostream>
using namespace std;
int main()
    {
       int row;
       cout << "Enter an integer" << endl;
       cin >> row;
       for (int i = 1; i <= row; ++i)
       {
           for (int j = row; j >= i; j--)
           {
               cout << '*';
           }
           cout << endl;
       }


    }

[Ganado]

I assume you mean

*****
 ****
  ***
   **
    *

Think of it like printing two distinct characters, except the o's become spaces:

*****
o****
oo***
ooo**
oooo*

So, every row, you need to print X amount of the first character, and (length - X) amount of the second character.

for (each row)
{
     for (X amount of times)
        print 'o'
     for (row - X amount of times)
        print '*'

    print newline
}

Once you see the pattern and can print it, change the 'o's back to spaces.

[seeplus]

You only need 1 for loop:

#include <iostream>
#include <iomanip>
using namespace std;

int main()
{
	int row;

	cout << "Enter an integer: ";
	cin >> row;

	for (int i = 0; i < row; ++i)
		cout << setfill('*') << setw(row - i + 1) << '\n';
}

or for right aligned,

#include <iostream>
#include <iomanip>
using namespace std;

int main()
{
	int row;

	cout << "Enter an integer: ";
	cin >> row;

	for (int i = 0; i < row; ++i)
		cout << setfill(' ') << setw(i) << "" << setfill('*') << setw(row - i + 1) << '\n';
}

[josh84]

Thanks guys. This is the code I ended with. It works well...

#include<iostream>
using namespace std;
int main()
{
     int i,k,j,n;
     cout << "Enter an integer" << endl;
     cin >> n;

     {
         k=0;
         for(i=n;i>0;i--)
         {
             for(j=1;j<=k;j++) std::cout<<" ";
             for(j=1;j<=i;j++) std::cout<<"*" ;

             std::cout<<"\n" ;
             k++;
         }

     }

}