how to??

[navi33]

Hi. im having a problem with 2 dimensional array.
im assigned to read the input of 45 names with corresponding gender, then display then and the number of males and females.
so far i got:
#include<iostream>


using namespace std;
int main()
{
char sname[45][4],row;
int male=0,female=0;
for (row=0;row<45;row++)
{
cout<<"\nEnter Last name: ";
cin>>sname[row][1];
cout<<"Enter First name: ";
cin>>sname[row][2];
cout<<"Enter mi: ";
cin>>sname[row][3];
cout<<"Enter gender: ";
cin>>sname[row][4];
do{
if (sname[row][4]=='m'||sname[row][4]=='M')
male++;
else if (sname[row][4]=='f'||sname[row][4]=='F')
female++;
else
cout<<"Invalid gende. Enter again.";
}while (sname[row][4]=='m'||sname[row][4]=='M'||sname[row][4]=='f'||sname[row][4]=='F');
}
row=0;
for (row=0;row<45;row++)
{
cout<<sname[row][1]<<", "<<sname[row][2]<<" "<<sname[row][3]<<" \n";
}
return 0;
}

but when i type more than 1 character the program passes the name codes as the number of character i typed...

pls help me Y_Y

sorry for the trouble DX

[z05DSL3A]

char sname[45][4] is an array of chars, cin>>sname[row][1]; can only put a single char into the array.

Do you know about std::string and struct yet?

This should get you going again:

#include <iostream>
#include <string>  

using namespace std;

int main()
{
    string sname[45][4];    //changed from a array of char to an array of strings
    int row=0, male=0,female=0; //row should be an int not a char
    for (row=0;row<45;row++)
    {
        cout<<"\nEnter Last name: ";
        cin>>sname[row][1];
        cout<<"Enter First name: ";
        cin>>sname[row][2];
        cout<<"Enter mi: ";
        cin>>sname[row][3];
        cout<<"Enter gender: ";
        cin>>sname[row][4];
        do{
            if (sname[row][4]=="m"||sname[row][4]=="M")  // changed character literals('') to string literals ("") 
                male++;
            else if (sname[row][4]=="f"||sname[row][4]=="F")
                female++;
            else
                cout<<"Invalid gende. Enter again.";
        }while (sname[row][4]=="m"||sname[row][4]=="M"||sname[row][4]=="f"||sname[row][4]=="F");
    }
    row=0;
    for (row=0;row<45;row++)
    {
        cout<<sname[row][1]<<", "<<sname[row][2]<<" "<<sname[row][3]<<" \n";
    }
    return 0;
}

[navi33]

we didn't tackle strings. so im getting a hard time doing this ><.

thx for the help. but why does the program hung up after i typed in the gender??

[z05DSL3A]

It looks like you need to put the cin>>sname[row][4]; inside the do...while loop, as it is the user does not get to enter a different gender if it is incorrect. Plus the logic is slightly wrong, you only want it to stay in the loop if those conditions are not true. e.g.
}while (!(sname[row][4]=="m"||sname[row][4]=="M"||sname[row][4]=="f"||sname[row][4]=="F"));

or do something like:

        bool invalid(false);
        do{
            invalid = false;
            cin>>sname[row][4];
            if (sname[row][4]=="m"||sname[row][4]=="M")   
                male++;
            else if (sname[row][4]=="f"||sname[row][4]=="F")
                female++;
            else
            {
                cout<<"Invalid gende. Enter again.";
                invalid = true;
            }
        }while (invalid);

[navi33]

woud try the first one since i don't know about bool.

i would like to know more about that bool thing...
(suck our professor doesn't teach that to us)

thx again

[z05DSL3A]

If you haven't already looked, take some time to go through this sites tutorials:
http://www.cplusplus.com/doc/tutorial/

[navi33]

ill try that

thx again~

[navi33]

can you please help me with this...

i forgot that the deadline of this is tommorow.

sorry for the trouble

[z05DSL3A]

Are you still trying to do the array?

if you wanted a single name you would do somthing like:
char yourname [20];

if you want first name, second name, you would do something like:
char yourname [2][20];

if you want space for 45 copies of first name, second name, you would do something like:
char names [45][2][20];

        cout<<"\nEnter Last name: ";
        cin>>sname[row][0][0];
        cout<<"Enter First name: ";
        cin>>sname[row][1][0];

[navi33]

Haha i just solved it now thx for the help~