array division problem

[KatipunanKKK]

Write a complete C program that will fill an array with int values read in from the keyboard, one per line, and outputs their sum as well as all the numbers read in, with each number annotated to say what percentage it contributes to the sum. Your program will ask the user how many integers there will be, that will determine the length of the array.
Sample Output:
How many integers will you enter?
4
Enter 4 integers, one per line:
2
1
1
2
The sum is 6.
The numbers are:
2 which is 33.33% of the sum.
1 which is 16.67% of the sum.
1 which is 16.67% of the sum.
2 which is 33.33% of the sum


I'm having problems with the division of arrays and instead of getting the percentage I only get 0.

#include<stdio.h>
#include<conio.h>
int main()
{
	int x,n,s=0,a;
	float y;
	printf("How many integers will you enter? \n");
	scanf("%d",&n);
	printf("Enter %d integers, one per line\n",n);
	int num[100];
	for(x=0;x<n;x++)
	{
		scanf("%d\n",&a);
		num[x]=a;
		s+=num[x];
	}
	printf("The sum is = %d\n",s);
	printf("The numbers are:\n");
	for(x=0;x<n;x++)
	{
		num[x]=a;
		y=a/s;
		printf("%d which is %f % of the sum\n",num[x],y);
	}
	getch();
	return 0;
}

[coder777]

Line 22 is an integer division. Cast either a or s to float.

Line 23: To show a % you need to double it: %%
See http://www.cplusplus.com/reference/cstdio/printf/?kw=printf

[KatipunanKKK]

Thank you very much :)

[AbstractionAnon]

Line 21: Why are you setting num[x] to a? a is a left over value from line 13.

Did you mean?

 
  a = num[x];