return doesn't work but cout does?

StupidLag (19)
this function from my class returns the size of length of the linked list.

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  int LinkedList::GetLength()
{
	int count = 0;
	Node* temp = head;
	while (temp!=0)
	{
		count++;
		temp = temp->next;
	}
	//cout << count;     <-- this works
	return count;
}
Peter87 (11238)
What do you mean doesn't work? Does the function not return the same value that is printed?
StupidLag (19)
it doesnt return anything at all. just a blank space
Moschops (7244)
That's impossible. It's returning an int, which will be 4 (or eight) bytes in size, and that memory will contain some value because it's impossible for it to not contain some value.

So what makes you think it's somehow a blank space?
Peter87 (11238)
Note that return doesn't automatically print the value. To print the value you need to do it explicitly.

 
 
cout << yourList.GetLength();
Last edited on
StupidLag (19)
output with return
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5
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5

5
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5
7

Press any key to continue . . .


output with cout
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5
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5

5
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5
7

6Press any key to continue . . . //notice the 6 over there?
StupidLag (19)
@peter

jesus christ. i can't believe i forgot that. im so focused on this thing i forgot the basics. so bad. thanks. DX
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