Operator Overloading

joeaswe1 (25)
I keep getting this error: error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'Complex' (or there is no acceptable conversion)
How do I fix it?

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#include <iostream>
#include <string>
using namespace std;


class Complex
{
	public:

		Complex();
		Complex(double r, double i)
		void operator >>(ostream& out); 
		void operator <<(istream& in); 
		friend Complex operator *(const Complex& first, const Complex& second);.
		friend Complex operator +(const Complex& first, const Complex& second);
		friend Complex operator -(const Complex& first, const Complex& second);

	private:

		double real;
		double imag;

};

Complex::Complex()
{
	real = 0;
	imag = 0;

}

Complex::Complex(double r, double i)
{
	real = r;
	imag = i;
}

void Complex::operator <<(istream& in)
{

	char op;
	char i;

	in >> real >> op >> imag >> i;

	if (op == '-')
	{
		imag = imag * -1;
	}
	return;
}
void Complex::operator >>(ostream& out) //prints a complex number to stream in the form a+bi
{

	out << real << "+" << imag << "i" << endl;

	if (imag < 0)
	{
		imag = imag + -1;
	}
	return;
}

Complex operator *(const Complex& first, const Complex& second)
{
	double result_real = (first.real * second.real) - (first.imag * second.imag);
	double result_imaginary = (first.real * second.imag) + (second.imag * second.real);
	return Complex(result_real, result_imaginary);

}
Complex operator +(const Complex& first, const Complex& second)
{
	double result_real = first.real + second.real;
	double result_imaginary = first.imag + second.imag;
	return Complex(result_real, result_imaginary);
}
Complex operator -(const Complex& first, const Complex& second)
{
	double result_real = first.real - second.real;
	double result_imaginary = first.imag - second.imag;
	return Complex(result_real, result_imaginary);
}

int main() {
	Complex a, b, c, d, e;
	cout << "Enter the values for a in the form x+yi: ";
	cin >> a;
	 cout << "Enter the values for b in the form x+yi: ";
	cin >> b;
	c = a + b;
	d = a - b;
	e = a*b;
	cout << "a is: " << a << "b is : " << b;
	cout << "a+b is: " << c << "a-b is: " << d << "a*b is: " << e;
	return 0;
}
Last edited on
MiiNiPaa (8886)
YOu declard operator << ( and >>) the way, you need Colles at the left and stream at the right: a << cout

IO operators should be nonmembers:
std::ostream& operator<<(std::ostream& out, const Complex& c)
joeaswe1 (25)
Great, I was able to fix it.

But how do I fix this, when someone enters a negative number for imag, I need it to output as subtraction.

e.g
Enter the values for a in the form x+yi:
-5+5i
Enter the values for b in the form x+yi:
-5+5i
a is: -5+5i
b is : -5+5i
a+b is: -10+10i
a-b is: 0+0i
a*b is: 0+-50i <<--- I need this to be 0-50i

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	friend istream &operator>>(istream &in, Complex &c)     //input
		{
			char op;
			char i;

			
			in >> c.real >> op >> c.imag >> i;

			if (op == '-')
			{
				c.imag = c.imag * -1;
			}
			
			return in;
		}
				
		
		friend ostream& operator<<(ostream &out, Complex c)     
		{
			if (c.imag < 0)
			{
				c.imag = c.imag * -1;
				((c.imag is lower than zero) ? '-' : '+')
			}
			out << c.real << '+' << c.imag << 'i';
			return out;
		}
MiiNiPaa (8886)
http://en.cppreference.com/w/cpp/io/manip/showpos
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int re = 5
int im = -1;

int re2 = -5
int im2 = 1;

std::cout << re  << std::showpos << im  << std::noshowpos << "i\n"; //5-1i
std::cout << re2 << std::showpos << im2 << std::noshowpos << "i\n"; //-5+1i
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