Calculator problem

[metalheadrenzo]

#include<stdio.h>
void addition();
void multiplication();
void division();
int main()
{
int opr;
printf("Renzo's calculator\n\n");

printf("Choose any desired operator\n");
printf("A: Addition\n\n");
printf("B: Multiplication\n\n");
printf("C: Division\n\n");
scanf("%d", &opr);

if (opr == 'A')
addition();

if (opr == 'B')
multiplication();

if (opr == 'C')
division();





return 0;
}

void addition()
{
int add1, add2, result;

printf("Input two number to be added\n");
scanf("%d", &add1);
scanf("%d", &add2);

result = add1+add2;

printf("%d", result);


}

void multiplication()
{
int mul1,mul2,result;

printf("Input numbers to be multiplied\n");
scanf("%d", &mul1);
scanf("%d",&mul2);

result = mul1*mul2;

printf("%d", result);



}

void division()
{
int div1,div2,result;

printf("Input numbers to be divided\n");
scanf("%d", &div1);
scanf("%d", &div2);

result = div1/div2;

printf("%d", result);


}

This is a running program btw but not running the way I wanted it to be. There's something wrong with my function call I guess.

There are no errors syntactically but probably in my logic. Can anyone spot the problem? Thanks.

[kbw]

This is the fourth time in 2 days I've had to post this.
http://www.cplusplus.com/forum/articles/1295/

[metalheadrenzo]

oh c'mon not even a hint?

[kbw]

Do you expect someone to try to work out what the program ought to be doing, then determine why it isn't doing it?

If you have a question ask it. Have you read the link I posted?

[MaikCAE]

That we can help you, we just want you to say:
1. This is my code
2. This is what it does
3. This is what I want it to do.

Point 1 you did. Ok, without using indents for a better view but you used the source-code tags, which is very helpfull for us to read.
But you missed Point 2 and 3. Also if there are no errors you could post. There should be some output or something like that which comes and which you don't want.

[metalheadrenzo]

Yes. Sorry bout that.

So, my problem is after I input my choice nothing happens. The only thing that appears is the letter I chose.

[MaikCAE]

Ok, now we know where to look for an error.

I don't know if it works with this change, but try to read a character instead of an integer.

char opr;
printf("Renzo's calculator\n\n");

printf("Choose any desired operator\n");
printf("A: Addition\n\n");
printf("B: Multiplication\n\n");
printf("C: Division\n\n");
scanf("%c", &opr);

if (opr == 'A') addition();

if (opr == 'B') multiplication();

if (opr == 'C') division();

[metalheadrenzo]

I didn't expect that.

Thanks MaikCAE. Sorry for the ignorance too

[MaikCAE]

No problem.
And it was just a hint for you how to write questions inside here if you want people to answer ;)