Idea please

dipen45 (21)
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/* Shown below is an Floyd's triangle*/
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4 5 6
7 8 9 10
11 .... 15
..
..
79 ......... 91
/* Give me the idea to generate this, thankq */
coder777 (8443)
the first loop goes from i=1 to i <= 91
the second inner loop goes from j=1 to j <= i
print out i in the inner loop
print out end of line after the inner loop
dipen45 (21)
I tried like this in C.
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#include <stdio.h>

int main()
{
	int i, j;
	
	for (i = 1; i <= 91; i++)
	{
		for (j = 1; j <= i; j++)
			printf("%d ", i);
	
	printf("\n");
	}
	
	return 0;	
				
}


but the code gives the wrong output.

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2 2 
3 3 3 
4 4 4 4 
5 5 5 5 5
.............
.............
91 91 ..............91


I know the variable i and j used here are to define the row and column but we don't exactly know the no of row.
Last edited on
dipen45 (21)
Ok after a little bit hard work. I solved this but with little bit odd way.
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#include <stdio.h>

int main()
{
	int i, j, num = 1;
	
	for (i = 1; i <= 91; i++)
	{
		for (j = 1; j <= i; j++)
		{
			printf("%d ", num);
			num++;
			if (num == 92)
				break;
		}
		
		printf("\n");
		if (num == 92)
			break;
	}
	
	return 0;
		
}



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2 3
4 5 6
7 8 9 10
11 12 13 14 15
16 17 18 19 20 21
...
...
79 80 81 82 83 84 85 86 87 88 89 90 91

Ok thanks coder777, Actutually i have to this using goto statment, I will do it.
Last edited on
coder777 (8443)
I solved this but with little bit odd way.
Ok, I didn't elaborate fully.
I'd say that your solution is completely ok. I don't see why it's supposed to be odd.

if you don't want the breaks you'd need to know the number of rows (on line 7) and do some more calculations
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