Initializing Arrays with Increment Operators
I'm currently taking my first C++ class, and the book has an example of declaring array values with an increment operator. When I first saw the code I thought that it was skipping position 0 of the array because of the increment, but when I run the code I can see that it's not. I am trying to understand why that's so.
The code I am referring to is below.
When I see that code I think: OK this is going to assign "rusty short sword" to inventory[1], because numItems is 0, and this array initialization increments numItems so it's actually going to be set to position 1 in the array, not 0.
However that doesn't seem to be the case, and I don't quite understand why. I can't find anything that explains this in more detail either. Can someone help shed some light on this?
The code I am referring to is below.
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When I see that code I think: OK this is going to assign "rusty short sword" to inventory[1], because numItems is 0, and this array initialization increments numItems so it's actually going to be set to position 1 in the array, not 0.
However that doesn't seem to be the case, and I don't quite understand why. I can't find anything that explains this in more detail either. Can someone help shed some light on this?
Last edited on
The postfix increment is handled after the array subscript.
Equivalent code:
The prefix increment will behave the way you describe:
Operator precedence: http://en.cppreference.com/w/cpp/language/operator_precedence
Equivalent code:
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The prefix increment will behave the way you describe:
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Operator precedence: http://en.cppreference.com/w/cpp/language/operator_precedence
Thank you for clarifying that - makes much more sense now. Seeing the equivalent code helps a lot.
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