Oct 23, 2013 at 5:59pm UTC
How would I go about summing up the individual rows and columns? Output would look like this
______ total
1 4 3 __ 7
5 6 2 __ 13
3 7 2 __ 12
9 12 7
total
Any input would be appreciated.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int A[10][10], i, j, r[10], c[10], row, col;
cout<<"Enter the number of rows & columns :\n" ;
cin>> row >> col;
cout << "Enter the Elements: \n" ;
for (i=0; i<row; ++i)
{
for (j=0; j<col; ++j)
{
cin>> A[i][j];
}
}
cout<< "\nGiven : " ;
for (i = 0; i<row; ++i)
{
cout<< "\n" ;
for (j = 0; j<col; ++j)
{
cout<< A[i][j]<< " " ;
}
}
cout<<"\n" ;
for (i=0; i<row; i++)
{
r[i] =0;
for (j=0; j<col; ++j)
{
r[i] += A[i][j];
}
}
for (j=0; j<col; ++j)
{
c[j] = 0;
for (i=0; i<row; ++i)
{
c[j] += A[i][j];
}
}
return 0;
}
Last edited on Oct 23, 2013 at 6:05pm UTC
Oct 23, 2013 at 6:21pm UTC
I think I would use vectors instead of fixed array. What do you do when col or row are greater than 10? Totals go in a vector(s) too...